1-16/x^2/1-4/x

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Solution for 1-16/x^2/1-4/x equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

1-(4/x)-((16/(x^2))/1) = 0

1-4*x^-1-16*x^-2 = 0

t_1 = x^-1

1-16*t_1^2-4*t_1^1 = 0

1-16*t_1^2-4*t_1 = 0

DELTA = (-4)^2-(-16*1*4)

DELTA = 80

DELTA > 0

t_1 = (80^(1/2)+4)/(-16*2) or t_1 = (4-80^(1/2))/(-16*2)

t_1 = (4*5^(1/2)+4)/(-32) or t_1 = (4-4*5^(1/2))/(-32)

t_1 = (4*5^(1/2)+4)/(-32)

x^-1-((4*5^(1/2)+4)/(-32)) = 0

1*x^-1 = (4*5^(1/2)+4)/(-32) // : 1

x^-1 = (4*5^(1/2)+4)/(-32)

-1 < 0

1/(x^1) = (4*5^(1/2)+4)/(-32) // * x^1

1 = ((4*5^(1/2)+4)/(-32))*x^1 // : (4*5^(1/2)+4)/(-32)

-32*(4*5^(1/2)+4)^-1 = x^1

x = -32*(4*5^(1/2)+4)^-1

t_1 = (4-4*5^(1/2))/(-32)

x^-1-((4-4*5^(1/2))/(-32)) = 0

1*x^-1 = (4-4*5^(1/2))/(-32) // : 1

x^-1 = (4-4*5^(1/2))/(-32)

-1 < 0

1/(x^1) = (4-4*5^(1/2))/(-32) // * x^1

1 = ((4-4*5^(1/2))/(-32))*x^1 // : (4-4*5^(1/2))/(-32)

-32*(4-4*5^(1/2))^-1 = x^1

x = -32*(4-4*5^(1/2))^-1

x in { -32*(4*5^(1/2)+4)^-1, -32*(4-4*5^(1/2))^-1 }

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